Package org.sonar.java.resolve
Class WildCardType
- java.lang.Object
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- org.sonar.java.resolve.JavaType
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- org.sonar.java.resolve.WildCardType
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Nested Class Summary
Nested Classes Modifier and Type Class Description static classWildCardType.BoundType-
Nested classes/interfaces inherited from interface org.sonar.plugins.java.api.semantic.Type
Type.ArrayType, Type.Primitives
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Constructor Summary
Constructors Constructor Description WildCardType(JavaType bound, WildCardType.BoundType boundType)
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description booleanisSubtypeOf(String fullyQualifiedName)Check whether a type is a subtype of the one designed by the fully qualified name.booleanisSubtypeOf(Type superType)Check whether a type is a subtype of another.booleanisSubtypeOfBound(JavaType type)-
Methods inherited from class org.sonar.java.resolve.JavaType
directSuperTypes, erasure, fullyQualifiedName, getSuperType, getSymbol, is, isArray, isClass, isNumerical, isParameterized, isPrimitive, isPrimitive, isPrimitiveWrapper, isTagged, isUnknown, isVoid, name, primitiveType, primitiveWrapperType, symbol, toString
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Constructor Detail
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WildCardType
public WildCardType(JavaType bound, WildCardType.BoundType boundType)
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Method Detail
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isSubtypeOf
public boolean isSubtypeOf(String fullyQualifiedName)
Description copied from interface:TypeCheck whether a type is a subtype of the one designed by the fully qualified name.This method will consider implemented interfaces as well as superclasses.
Type type; type.isSubtypeOf("Object[]"); type.isSubtypeOf("org.mypackage.MyClass"); type.isSubtypeOf("org.mypackage.MyInterface"); type.isSubtypeOf("java.lang.Object");- Specified by:
isSubtypeOfin interfaceType- Overrides:
isSubtypeOfin classJavaType- Parameters:
fullyQualifiedName- fully qualified name to check in the type hierarchy. Use "[]" for arrays.- Returns:
- true if the type is the one passed in parameter or have this type in its hierarchy. false otherwise.
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isSubtypeOf
public boolean isSubtypeOf(Type superType)
Description copied from interface:TypeCheck whether a type is a subtype of another.This method will consider implemented interfaces as well as superclasses.
Type type, myOtherType; type.isSubtypeOf(myOtherType);
- Specified by:
isSubtypeOfin interfaceType- Overrides:
isSubtypeOfin classJavaType- Parameters:
superType- instance of a potential superType.- Returns:
- true if types are equivalent or if the one passed in parameter is in the hierarchy. false otherwise.
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isSubtypeOfBound
public boolean isSubtypeOfBound(JavaType type)
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